H2 Maths Notes (JC 1-2): 6.1) Probability
Download printable cheat-sheet (CC-BY 4.0)07 Oct 2025, 00:00 Z
Study cadence\ Tighten your language: every time you quote a probability, state the event clearly first. Keep a running list of assumptions (mutually exclusive, independent, equally likely) before applying shortcuts.
Core Definitions
- Sample space ( S ) contains all mutually exclusive outcomes.
- Event ( A \subseteq S ) has probability ( P(A) = ) number of favourable outcomes divided by number of total outcomes (for equally likely cases) or the frequency assigned by the model.
- Complement: ( P(A^c) = 1 - P(A) ).
- Addition law: ( P(A \cup B) = P(A) + P(B) - P(A \cap B) ).
- Conditional probability: ( P(A \mid B) = \frac{P(A \cap B)}{P(B)} ) whenever ( P(B) > 0 ).
- Independence: ( A ) and ( B ) are independent if ( P(A \cap B) = P(A) P(B) ); equivalently ( P(A \mid B) = P(A) ) and ( P(B \mid A) = P(B) ).
Diagram Workflows
Venn diagrams
- Label each region with algebraic expressions (e.g. ( x ) for the overlap, ( 0.4 - x ) for the remaining part of ( A )).
- Use the total probability constraint (sum of all regions equals 1) to solve for the unknowns.
- When three sets appear, build the diagram region by region, starting from the three-way overlap.
Example -- Scholarship shortlisting
Let ( A ) be "strong portfolio" and ( B ) be "strong interview". Given ( P(A) = 0.65 ), ( P(B) = 0.55 ), and ( P(A \cap B) = 0.42 ):
- ( P(A^c \cap B) = 0.55 - 0.42 = 0.13 ).
- ( P(A \cap B^c) = 0.65 - 0.42 = 0.23 ).
- ( P(A^c \cap B^c) = 1 - 0.65 - 0.55 + 0.42 = 0.22 ).
- ( P(A \mid B) = \frac{0.42}{0.55} \approx 0.764 ).
Tree diagrams
- Multiply along branches to obtain joint probabilities (e.g. ( P(A \cap B) = P(A) P(B \mid A) )).
- Sum the relevant final nodes to find the total probability of an event.
- When conditional information is provided about the second stage, write it beside the branches before multiplying.
Example -- Quality control
A factory inspects items with two stages:
- Stage 1: pass with probability 0.9.
- Stage 2: conditional pass probability is 0.95 if Stage 1 passed, 0.6 if Stage 1 failed.
Compute the probability of an item passing both stages:
- Branch values:
pass
thenpass
has probability ( 0.9 \times 0.95 = 0.855 ). - If the second stage pass probability is to be found given the item passed Stage 2, apply Bayes:
- Total Stage 2 pass probability = ( 0.9 \times 0.95 + 0.1 \times 0.6 = 0.915 ).
- Probability an item passed Stage 1 given it passed Stage 2 = ( \frac{0.855}{0.915} \approx 0.935 ).
Common Question Types
Showing independence (or dependence)
- Compute both ( P(A \cap B) ) and ( P(A) P(B) ); equality means independent, inequality means dependent.
- Alternatively, compare ( P(A \mid B) ) with ( P(A) ).
Conditional complements
- ( P(A^c \mid B) = 1 - P(A \mid B) ).
- When the question gives the probability of "at least one" event happening, convert to the complement of "none".
Total probability rule
For a partition ( B_1, B_2, \dots, B_k ) of the sample space:
[ P(A) = \sum_{i=1}^{k} P(A \mid B_i) P(B_i). ]
In H2 questions this often appears in genetics or reliability contexts.
Calculator and Notation Tips
- Casio: use the
TREE
mode to visualise multi-stage events; store intermediate probabilities in variablesA
,B
,C
if you need to reuse them across branches. - TI: use lists to capture outcomes and apply
cumSum
to compute running totals for "at least" or "at most" questions. - Always define events in words before introducing symbols; MOE marking schemes penalise answers that show algebra without context.
Exam Watch Points
- State assumptions (mutually exclusive or independent) explicitly before cancelling terms.
- For sequential processes, highlight whether sampling is with or without replacement; it changes conditional probabilities immediately.
- When using Bayes, write out the denominator expansion so the marker sees the full weighting.
- Double-check rounding: most questions accept 3 significant figures unless stated otherwise.
Quick Revision Checklist
- [ ] Convert word problems into formal event notation consistently.
- [ ] Draw and label Venn or tree diagrams before solving algebraically.
- [ ] Execute conditional probability calculations without skipping intermediate steps.
- [ ] Distinguish between mutually exclusive and independent events (they are not the same).
- [ ] Apply total probability and Bayes reliably under time pressure.
Next steps: practise 2-by-2 Bayes table questions (medical testing, customer segmentation) and extend into the discrete random variable toolkit covered in Topic 6.2.