H2 Chemistry 12 - Electrochemistry: EMF Calculation from Standard Electrode Potentials

What you will learn

• Zn / Zn2+ at -0.76 V and Cu / Cu2+ at +0.34 V; the more negative half-cell is oxidised (anode), the more positive is reduced (cathode).
• Cell EMF = E(cathode) minus E(anode) = +0.34 minus (-0.76) = +1.10 V; positive value means the reaction is feasible under standard conditions.
• Overall: Zn(s) + Cu2+(aq) -> Zn2+(aq) + Cu(s); electrons flow Zn to Cu through the external wire.