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A short H2 Chemistry revision video on H2 Chemistry 12 - Electrochemistry: EMF Calculation from Standard Electrode Potentials, built for quick recap before tutorial practice or exam revision.
Read through the explanation after watching, or jump straight to the step you want to replay.
Step 1 - State the problem
Calculate the standard cell potential for the electrochemical cell made from zinc and copper half-cells.
Step 1 - State the problem
The standard electrode potential of zinc two plus slash zinc is minus zero point seven six volts.
Step 1 - State the problem
The standard electrode potential of copper two plus slash copper is plus zero point three four volts.
Step 1 - State the problem
Determine which electrode is the anode and which is the cathode, and write the overall cell equation.
Step 2 - Identify anode and cathode
The half-cell with the more negative electrode potential is oxidised - it becomes the anode.
Step 2 - Identify anode and cathode
Zinc has the more negative value at minus zero point seven six volts, so zinc is the anode.
Step 2 - Identify anode and cathode
Copper has the more positive value at plus zero point three four volts, so copper is the cathode.
Step 2 - Identify anode and cathode
Remember: oxidation occurs at the anode, and reduction occurs at the cathode.
Step 3 - Calculate the standard cell EMF
The standard cell EMF equals E cathode minus E anode.
Step 3 - Calculate the standard cell EMF
That is plus zero point three four minus the bracket minus zero point seven six.
Step 3 - Calculate the standard cell EMF
Zero point three four plus zero point seven six equals plus one point one zero volts.
Step 3 - Calculate the standard cell EMF
A positive EMF confirms that the reaction is feasible under standard conditions.
Step 4 - Write the overall cell equation
Add the two half-equations together.
Step 4 - Write the overall cell equation
The electrons cancel because both half-equations involve two electrons.
Step 4 - Write the overall cell equation
The overall equation is: zinc solid plus copper two plus ions give zinc two plus ions plus copper solid.
Step 4 - Write the overall cell equation
Zinc is oxidised and copper two plus is reduced. Electrons flow from the zinc electrode to the copper electrode through the external circuit.
Step 5 - Link EMF to Gibbs free energy and common pitfalls
The standard Gibbs free energy change is related to EMF by the equation delta G equals minus n F E.
Step 5 - Link EMF to Gibbs free energy and common pitfalls
Here n is two moles of electrons, F is the Faraday constant at ninety-six thousand five hundred coulombs per mole, and E is one point one zero volts.
Step 5 - Link EMF to Gibbs free energy and common pitfalls
Delta G equals minus two times ninety-six thousand five hundred times one point one zero, which is minus two hundred and twelve kilojoules per mole. The negative value confirms spontaneity.
Step 5 - Link EMF to Gibbs free energy and common pitfalls
Common mistake: using E anode minus E cathode instead of E cathode minus E anode. Always subtract the anode from the cathode.