Loading page…
Loading page…
A short H2 Maths revision video on H2 Maths 5.2 - Maclaurin Series: Multiplying Two Expansions, built for quick recap before tutorial practice or exam revision.
Read through the explanation after watching, or jump straight to the step you want to replay.
Step 1 - Set up the problem
We want the Maclaurin series of e to the two x times cosine x, up to and including the x cubed term.
Step 1 - Set up the problem
The strategy is to expand each factor separately using standard templates,
Step 1 - Set up the problem
then multiply the truncated polynomials and collect by power of x.
Step 2 - Expand e to the 2x
Start from the standard e to the x series.
Step 2 - Expand e to the 2x
Substitute two x in place of x throughout.
Step 2 - Expand e to the 2x
Two x all squared over two factorial is four x squared over two, which simplifies to two x squared.
Step 2 - Expand e to the 2x
Two x all cubed over three factorial is eight x cubed over six, which simplifies to four thirds x cubed.
Step 3 - Write the cos x terms needed
Cosine x has only even powers: one minus x squared over two factorial plus x to the four over four factorial, and so on.
Step 3 - Write the cos x terms needed
For our product up to x cubed, we only need cosine x up to x squared.
Step 3 - Write the cos x terms needed
The x to the four term, multiplied by the constant one from e to the two x, would give x to the four - which we discard.
Step 3 - Write the cos x terms needed
So we truncate cosine x at x squared.
Step 4 - Multiply and collect by power
Now multiply the two truncated series term by term, keeping only powers up to x cubed.
Step 4 - Multiply and collect by power
The constant and x and x squared rows each come from one cross-product.
Step 4 - Multiply and collect by power
The x cubed row gets two contributions: four thirds x cubed from the e to the two x factor,
Step 4 - Multiply and collect by power
and two x times negative x squared over two, which is negative x cubed.
Step 4 - Multiply and collect by power
Four thirds minus one is one third.
Step 5 - Final answer and exam watch points
So the Maclaurin expansion of e to the two x cosine x up to x cubed is: one plus two x plus three halves x squared plus one third x cubed.
Step 5 - Final answer and exam watch points
Three exam watch points.
Step 5 - Final answer and exam watch points
Keep factorial denominators exact - do not evaluate two factorial to two until the final simplification.
Step 5 - Final answer and exam watch points
State the remainder order explicitly: plus order x to the four.
Step 5 - Final answer and exam watch points
Both e to the x and cosine x converge for all x, so no validity restriction is needed here.