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H2 Physics 19 - Quantum Physics: Photoelectric Effect Calculation

What you will learn

UV at lambda = 250 nm on a metal with work function phi = 3.5 eV; find photon energy, check threshold, and find KE_max.
Photon energy E = h c / lambda = 7.96 x 10^-19 J which is about 4.97 eV.
4.97 eV is greater than 3.5 eV, so emission occurs; KE_max = E minus phi = 1.47 eV.

Continue H2 Physics Quantum Physics Notes | A-Level 9478

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