H2 Physics Circular Motion Notes | A-Level 9478

Study guideUpdated 21 Aug 2026
Q: What does A-Level Physics: 7) Circular Motion Guide cover?
A: From angular displacement to centripetal force, this guide unpacks Topic 7 of the 2026 H2 Physics syllabus for IP students and parents.
TL;DR
Circular motion looks deceptively “plug-and-chug”, but it underpins vertical-circle forces, banked tracks, and conical pendulums - and it feeds directly into gravitation, satellites and SHM later. Nail radians, v=rω v = r \omega , a=rω2 a = r \omega^2 and F=mv2r F = \dfrac{mv^2}{r} early to free up mental bandwidth for the harder integrations later in the IP track.

Concrete example: how to use this page

For a car turning a corner, do not invent an outward force. Draw the real force that points inward, then set it equal to mv2/rmv^2/r. The same habit works for strings, tracks, and satellites.

Cross-reference our free H2 Physics notes for adjoining gravitation/SHM chapters and downloadable drills so your revision plan follows the full Topic 7→Topic 9 arc. For the full topic map and paper weightings, see our H2 Physics Syllabus 2026-27 overview.


1 Where this fits in the syllabus

The SEAB 2026 H2 Physics syllabus positions Circular Motion as Topic 7 in Section I - Mechanics. IP schools typically teach it right after Dynamics so that normal-reaction questions in vertical circles feel like natural extensions.

1.1 Why parents should care

Sign slips in the radial direction (and mixing up centripetal vs “centrifugal” language) are common sources of lost method marks early on; fixing them early makes later gravitation/satellite/SHM work much smoother.


2 Angular displacement in radians

Radians measure “arc length per radius”, making every calculus derivative in later topics cleaner.

  • Quick check: Half a revolution = π\pi rad (=180= 180^{\circ}).
  • WA tip: Always label the axis on your graph in radians (not degrees) to avoid losing easy accuracy marks.

3 Angular velocity ω \omega

Define: ω=ΔθΔt \omega = \dfrac{\Delta \theta}{\Delta t} with θ \theta in radians and ω \omega in s1 \pu{s-1}

v=rω. v = r \omega.

This falls straight out of “distance = rate × time” when the arc length s=rθ s = r \theta is divided by t t .


4 Centripetal acceleration ac a_c

Uniform circular motion means the speed is constant but the velocity changes direction, producing an inward acceleration

ac=rω2=v2r. a_c = r \omega^2 = \dfrac{v^2}{r}.

Direction: Always toward the geometric centre, perpendicular to v v .

Intuitive cue: Rotate the velocity vector by 90° then scale it by vr \dfrac{v}{r} .


5 Centripetal force Fc F_c

Newton's Second Law packages the previous result into

Fc=mac=mrω2=mv2r. F_c = m a_c = m r \omega^2 = \dfrac{m v^2}{r}.

The sharper the bend (small rr) or the faster the motion (large vv), the larger the required inward force.

5.1 Radial force setup routine

Use this routine before substituting into F=mv2rF = \dfrac{mv^2}{r}. It keeps "centripetal force" as a resultant, not a new force to add to the diagram.

StepWhat to doExample check
1Mark the centre of the circleFor a vertical loop, the centre is inside the loop
2Draw the radial arrow toward the centreAt the top, inward is downward; at the bottom, inward is upward
3List only real forces on the objectWeight, tension, normal reaction, friction, or thrust
4Resolve forces along the radial directionForces pointing inward are positive in the radial equation
5Set radial resultant equal to mv2r\dfrac{mv^2}{r}

Worked force map:

Position / scenarioInward directionRadial equation
Mass on a horizontal stringToward the hand or centreT=mv2rT = \dfrac{mv^2}{r}
Car at the top of a convex hill

Trap check: if your free-body diagram contains a separate arrow labelled "centripetal force", redraw it. The inward resultant is made from real forces already on the object.

5.2 Common exam archetypes

ScenarioCatchRemedy
Car cresting a hillNormal reaction can drop to zeroEquate weight to centripetal requirement
Roller coaster loopRadial direction flips at the topDraw FBD for each quadrant
Conical pendulumResolve tension into radial and vertical componentsUse Tcosθ=mg T \cos\theta = mg then Tsinθ=mv2r T \sin\theta = \dfrac{mv^2}{r}

6 Mini-drill (3 min)

  1. Express 720° in radians.
    Answer: 4π rad 4 \pi \text{ rad} .
  2. Solve: A 0.40kg 0.40 \pu{kg} mass whirls at 5.0ms1 5.0 \pu{m.s-1} in a horizontal circle on a 0.60m 0.60 \pu{m}

7 Bridging to Paper 4 practical

To verify Fc=mv2r F_c = \dfrac{m v^2}{r} experimentally, keep one variable fixed and plot a straight-line graph:

  • fixed rr: plot FcF_c against v2v^2 → gradient =m/r= m/r

Always quote ± \pm one standard error from the LINEST output.


8 Three WA timing rules

  1. Use syllabus pacing as a guide: Paper 2/3 average ~1.6 min/mark; Paper 4 ~3 min/mark.
  2. Write the radial direction beside your FBD before summing forces.
  3. Keep units visible; missing the “per-second-squared” costs one accuracy mark.

Need structured practice on Circular Motion? Our H2 Physics tuition programme covers this topic with weekly problem sets and Paper 4 practical drills.


Comprehensive revision pack

9478 Section II, Topic 7 Syllabus outcomes

Candidates should be able to:

  • (a) express angular displacement in radians.
  • (b) show an understanding of and use the concept of angular velocity.
  • (c) recall and use v=rω v = r\omega to solve problems.
  • (d) show an understanding of centripetal acceleration in the case of uniform motion in a circle, and qualitatively describe motion in a curved path (arc) as due to a resultant force that is both perpendicular to the motion and centripetal in direction.
  • (e) recall and use centripetal acceleration a=rω2 a = r\omega^2 , and a=v2r a = \dfrac{v^2}{r}

Concept map (in words)

Convert to radians, compute angular quantities, then translate back to linear variables when forces are required. Always identify the radial direction because the net inward force equals mv2r \dfrac{m v^2}{r} . Vertical situations demand additional energy/force checks at top and bottom. Banked motion and conical pendula link circular motion to equilibrium concepts from Topic 2.

Key relations

QuantityExpression
Angular velocityω=ΔθΔt \omega = \dfrac{\Delta \theta}{\Delta t}
Angular accelerationα=ΔωΔt \alpha = \dfrac{\Delta \omega}{\Delta t}

Derivations & reasoning to master

  1. Centripetal acceleration: derive ac=v2r a_c = \dfrac{v^2}{r} using vector subtraction or calculus (limit of chord angles).
  2. Banked-track formula: resolve normal reaction components and solve for frictionless optimum.
  3. Vertical circle tension: write Newton's 2nd law at top and bottom, showing how minimum speed arises from T0 T \ge 0

Vertical-loop contact checkpoint

For vertical-circle questions, decide first whether the object is held by a string, pressed by a track, or just maintaining contact with a surface. The radial equation changes because the real inward forces change at each position.

Position or clueInward directionSetup moveCommon trap
Top of an inside loopDownwardWeight and normal reaction both point inward: mg+N=mv2rmg + N = \dfrac{mv^2}{r}

Worked check: if a cart just maintains contact at the top of a loop of radius 1.8 m\pu{1.8 m}, then

mg=mv2rv=gr=9.81×1.84.2 ms1. mg = \dfrac{mv^2}{r} \Rightarrow v = \sqrt{gr} = \sqrt{9.81 \times 1.8} \approx \pu{4.2 m.s-1}.

Misconception check: the normal reaction becomes zero at the limiting top speed, but weight is still acting and still supplies the required inward resultant.

Worked example 1 - vertical loop

A 0.50 kg \pu{0.50 kg} cart enters a vertical loop of radius 1.8m 1.8 \pu{m} at 12ms1 12 \pu{m.s-1} at the bottom. Find (a) its speed at the top (neglect friction), (b) the normal reaction at the top and bottom.

Sketch solution: use energy to determine the speed at the top v2=u24gR v^2 = u^2 - 4 g R . Substitute into mv2r \dfrac{m v^2}{r}

Taking g=9.81 ms2g = \pu{9.81 m.s-2},

v=1224g(1.8)8.56 ms1. v = \sqrt{12^2 - 4g(1.8)} \approx \pu{8.56 m.s-1}.

Top: N=0.50×v21.80.50g15.5 NN = \dfrac{0.50\times v^2}{1.8} - 0.50g \approx \pu{15.5 N}.

Worked example 2 - conical pendulum

A 0.25 kg \pu{0.25 kg} bob moves in a horizontal circle of radius 0.65m 0.65 \pu{m} with period 1.7s 1.7 \pu{s} . Determine the string tension and the angle it makes with the vertical.

Approach: compute angular speed ω=2πT \omega = \dfrac{2 \pi}{T} , then v=rω v = r \omega . Apply the radial equation Tsinθ=mv2r T \sin\theta = \dfrac{m v^2}{r}

ω=2π1.73.70 s1,v=0.65ω2.40 ms1. \omega = \dfrac{2\pi}{1.7} \approx \pu{3.70 s-1},\qquad v = 0.65\,\omega \approx \pu{2.40 m.s-1}.

tanθ=v2rg0.904    θ42 ,T=mgcosθ3.31 N. \tan\theta = \dfrac{v^2}{rg} \approx 0.904\;\Rightarrow\; \theta \approx \pu{42^{\circ}},\qquad T = \dfrac{mg}{\cos\theta} \approx \pu{3.31 N}.

Practical & data tasks

  • Perform a whirling bung experiment; plot v2 v^2 vs radius and extract g g from the gradient.
  • Use accelerometer data on a rotating turntable to compare measured radial acceleration with v2r \dfrac{v^2}{r}

Common misconceptions & exam traps

  • Treating “centripetal force” as a new force; it is just the resultant toward the centre.
  • Using mg=mv2r mg = \dfrac{m v^2}{r} blindly without checking position in the vertical circle.
  • Mixing tangential and radial components when acceleration is not uniform.
  • Forgetting to convert revolutions per minute to radians per second.

Quick self-check quiz

  1. Express 3 revolutions per second in rads1 \pu{rad.s-1} . - 6 πrads1\pu{ 6 \pi rad.s-1} .
  2. What provides the centripetal force for a satellite in circular orbit? -

Revision workflow

  1. Redo three past-paper problems covering vertical circles, conical pendula and banked tracks.
  2. Re-derive ac=v2r a_c = \dfrac{v^2}{r} weekly to keep the concept fresh.
  3. Create a table comparing radial forces in different contexts (tension, weight, normal, electrostatic).
  4. Practise sketching velocity and acceleration vectors for points around a circle without referencing notes.

Practice Quiz

Test yourself on the key concepts from this guide.


9 Further reading


10 Call-to-action

Parents: Book a 60-min Circular Motion clinic before WA 2 to bullet-proof free-body diagrams. Students: Paste ac=v2r a_c = \dfrac{v^2}{r} on your water-bottle and test it on tomorrow's vertical-circle worksheet.

Last updated 14 Jul 2025. Next review when SEAB issues the 2027 draft syllabus.

Keep studying with Eclat

Join the Telegram study group for new notes, quizzes, and study resources.

Join our Telegram study group
Chee Wei Jie
Reviewed by
Chee Wei Jie·Academic Advisor (Physics)

Sources

  1. SEAB: GCE A-Level H2 Physics (9478) syllabus (first examination 2026) (PDF)