H2 Chemistry QA: Identifying Two Cations and Two Anions in One Sample (Paper 4 Walkthrough)
14 Apr 2026, 00:00 Z
Want small-group support? Browse our A-Level Chemistry Tuition hub. Not sure which level to start with? Visit Chemistry Tuition Singapore.
Looking for the full lab practical series? Visit the H2 Chemistry Practicals.
Practical course completion-record note
For practical, lab, and experiment courses, Eclat Institute maintains centre-held attendance records and may also issue an internal attendance or completion document based on participation and internal assessment.
- For SEAB private-candidate declarations, the key evidence is the centre's attendance or completion record, not a government-issued certificate.
- This is an internal centre-issued certificate, not an MOE/SEAB qualification or accreditation.
- Recognition (if any) is determined by the receiving school, institution, or employer.
- For SEAB private candidates taking science practical papers, SEAB states you should either have taken the subject before or attend a practical course and complete it before the practical paper date.
View our sample completion document (Current sample layout (design may be refined over time))
Planning a revision session? Use our study places near me map to find libraries, community study rooms, and late-night spots.
> **Q:** Why do two-cation two-anion samples appear in Paper 4, and what is different about analysing them?\
> **A:** Single-ion unknowns are common in school practice but rare in exam conditions. SEAB Paper 4 regularly presents samples that contain two distinct cations and two distinct anions. Each reagent you add interacts with all ions present simultaneously, so precipitate colours can blend, confirmatory tests can be masked, and a naive sequence can cost you three or four marks in a single observation line. This post is a complete walkthrough of the logic and phrasing you need.
> **TL;DR**\
> When a sample contains two cations and two anions, no single reagent gives a clean observation. You must work in a deliberate sequence: preliminary tests first to narrow the field, then cation isolation using NaOH and NH₃, then anion isolation using acidified AgNO₃ and BaCl₂. Observation phrasing must account for mixed precipitates. The worked example below uses $\text{Cu}^{2+}$, $\text{Fe}^{3+}$, $\text{SO}_4^{2-}$, and $\text{Cl}^{-}$ as a representative hard case.\
> Before reading this post, make sure you have the foundational workflow from [Qualitative Analysis and Organic Workflow for H2 Chemistry Paper 4](https://eclatinstitute.sg/blog/h2-chemistry-experiments/H2-Chemistry-Qualitative-Analysis-Workflow). This post builds directly on that foundation.
*Status:* SEAB H2 Chemistry (9476) first examined 2026. QA notes are supplied in Paper 4, but reagent choice, test sequence, and observation phrasing are not. This post is aligned with the 9476 syllabus ion list and specimen Paper 4 expectations. [1]
---
## 1 | Why two-cation two-anion samples are the hardest QA case
In a standard school QA exercise the unknown contains one cation. Add NaOH: one colour precipitate. Add NH₃: one solubility behaviour. The observation is clean and the inference follows directly from the supplied QA notes.
Paper 4 raises the difficulty by mixing two cations in the same solution. The consequences are non-trivial:
**Precipitate blending.** When you add NaOH to a solution containing both $\text{Cu}^{2+}$ and $\text{Fe}^{3+}$, you do not see two separate coloured precipitates forming on opposite sides of the tube. You see a mixed precipitate. If the Fe³⁺ concentration is high, the reddish-brown of iron(III) hydroxide can overwhelm the pale blue of copper(II) hydroxide, and a careless student writes "brown precipitate" and misses the copper entirely.
**Masking.** Some anion tests rely on the supernatant being colourless or lightly coloured. If the background cation solution is blue or yellow, a pale white precipitate may not be visible without careful technique.
**Sequence dependence.** Adding acidified AgNO₃ to test for Cl⁻ in the presence of $\text{SO}_4^{2-}$ gives two precipitates: white AgCl and white BaSO₄ (if Ba²⁺ were present), but actually both AgCl and Ag₂SO₄ can form. You need to know which confirmatory step distinguishes them.
**Mark allocation.** In Paper 4 mark schemes, a single observation line can carry two marks: one for the correct colour and one for correct inference. If you observe "white precipitate" without specifying which anion is responsible, or "precipitate" without the colour, you typically receive zero for that line regardless of whether your later inference is correct.
The two-cation two-anion case demands that you treat each test as a filter, not a verdict.
---
## 2 | Decision tree overview: why the preliminary phase is load-bearing
The preliminary phase — flame test, acid test for carbonate, sniff test for ammonium — is load-bearing in multi-ion samples because it simultaneously constrains both cations and anions before any reagent chemistry begins.
**Flame test.** A persistent brick-red flame immediately raises the probability of Ca²⁺. A green-blue flame points to Cu²⁺. No flame colour is also evidence: the absence of a yellow (Na⁺) or lilac (K⁺) flame removes those cations from the candidate list. When two cations are present, one flame colour can mask the other, but a strong, persistent colour is still diagnostic.
**Acid test.** Adding dilute hydrochloric acid to the solid or solution releases CO₂ (limewater → milky) if carbonate or hydrogencarbonate is present. This eliminates or confirms one class of anion immediately. It also tells you whether your solution will effervesce during later acid-addition steps — which changes how you interpret gas evolution in subsequent tests.
**Ammonium test.** Warming the sample with NaOH releases NH₃ (moist red litmus → blue) if NH₄⁺ is present. This is a cation test, and it is best done early before you have added excess NaOH for the cation precipitation phase, because the excess NaOH you use later would also evolve NH₃ and you would not be able to attribute the gas to the sample vs the reagent.
**Why this matters for the multi-ion case.** If the preliminary phase tells you the sample has no carbonate and no ammonium, your cation candidates are the transition metals and Group II ions only. If the flame test is positive for one specific cation, you can confirm it quickly in the cation phase and spend more attention on separating the second unknown cation.
---
## 3 | Cation isolation logic: NaOH and NH₃
The cation isolation sequence in the supplied QA notes runs: NaOH dropwise → NaOH in excess → NH₃ dropwise → NH₃ in excess.
The critical skill for multi-cation samples is reading the **combined precipitate observation correctly** and using solubility in excess as the distinguishing step.
### 3.1 NaOH dropwise and excess
When NaOH is added dropwise to a two-cation sample, both hydroxides precipitate simultaneously. The colour you observe is a blend of the two. This is your first reading of the mixture. Adding excess NaOH then selectively dissolves amphoteric hydroxides (Al(OH)₃, Zn(OH)₂, Pb(OH)₂ dissolve; Cu(OH)₂, Fe(OH)₃, Mg(OH)₂ do not).
### 3.2 NH₃ dropwise and excess
Adding NH₃ dropwise may give additional precipitation for cations not fully precipitated at neutral pH. Excess NH₃ selectively dissolves the hydroxides of Cu²⁺ (to give deep blue $[\text{Cu(NH}_3)_4]^{2+}$) and Zn²⁺ (to give colourless $[\text{Zn(NH}_3)_4]^{2+}$), but not Fe³⁺ or Al³⁺.
### 3.3 Combined observation table: Cu²⁺ and Fe³⁺
The worked example below shows how observations differ when each cation is present alone vs together.
| Reagent | Observation if Cu²⁺ only | Observation if Fe³⁺ only | Observation if both present |
| --- | --- | --- | --- |
| NaOH dropwise | Pale blue gelatinous precipitate | Reddish-brown precipitate | Mixed brown precipitate with possible blue tinge |
| NaOH in excess | Precipitate remains, does not dissolve | Precipitate remains, does not dissolve | Mixed precipitate remains |
| NH₃ dropwise | Pale blue precipitate | Reddish-brown precipitate remains | Mixed precipitate, reddish-brown persists |
| NH₃ in excess | Precipitate dissolves; deep blue solution | Precipitate remains, insoluble in excess NH₃ | Blue portion dissolves, reddish-brown residue remains |
**Key inference point.** If excess NH₃ gives a deep blue solution **and** leaves a reddish-brown residue that does not dissolve, you can confidently infer both Cu²⁺ and Fe³⁺ are present. This is the split observation that earns both marks.
---
## 4 | Anion isolation logic: acidified AgNO₃ and BaCl₂
Anion tests must be done on the **original sample** or a fresh aliquot — not on the supernatant from cation precipitation, because excess NaOH or NH₃ will interfere.
### 4.1 Cl⁻ identification
Add acidified silver nitrate (dilute HNO₃ + AgNO₃) to a fresh aliquot of the sample. A white precipitate that is **insoluble in dilute NH₃** indicates Cl⁻. (AgBr gives a cream precipitate, partially soluble; AgI gives a yellow precipitate, insoluble. The solubility in NH₃ distinguishes them.)
If $\text{Cu}^{2+}$ is present, the solution background is blue before precipitation. The white AgCl forms against a blue background. Work against a white tile to see it clearly.
### 4.2 SO₄²⁻ identification
Add acidified barium chloride (dilute HCl + BaCl₂) to a fresh aliquot. A white precipitate that is **insoluble in dilute HCl** indicates SO₄²⁻. The acid ensures that BaSO₃ (from sulfite) does not form — sulfite is soluble in acid, so any precipitate that persists is genuinely BaSO₄.
Note: do not use H₂SO₄ to acidify. Use HCl only, because H₂SO₄ itself contains $\text{SO}_4^{2-}$ and would give a false positive.
### 4.3 Combined observation table: Cl⁻ and SO₄²⁻
| Reagent | Observation if Cl⁻ only | Observation if SO₄²⁻ only | Observation if both present |
| --- | --- | --- | --- |
| Acidified AgNO₃ | White precipitate, insoluble in dilute HNO₃, dissolves in excess NH₃ | No precipitate (Ag₂SO₄ is slightly soluble) | White precipitate forms; partially dissolves in excess NH₃ (AgCl dissolves; Ag₂SO₄ precipitate may remain as a faint haze) |
| Acidified BaCl₂ | No precipitate | White precipitate, insoluble in dilute HCl | White precipitate, insoluble in dilute HCl |
**For the mixed case**, use acidified BaCl₂ first. A clean white precipitate confirms SO₄²⁻. Then use acidified AgNO₃ on a separate aliquot to test for Cl⁻ without the interference of Ba²⁺ forming BaSO₄ with your reagent.
---
## 5 | Interference patterns and masking
### 5.1 Two cations that give the same precipitate colour
Al³⁺ and Mg²⁺ both give white gelatinous precipitates with NaOH. Adding NaOH to a sample containing both produces a white gelatinous precipitate that tells you nothing about which ion is present.
**Resolution.** Add NaOH in excess. Al(OH)₃ dissolves (amphoteric) to give a colourless solution. Mg(OH)₂ does not dissolve. If the precipitate partially dissolves in excess, both may be present — you need to observe whether a residue remains after dissolution of the soluble fraction.
Then add NH₃ in excess. Neither Al³⁺ nor Mg²⁺ gives a soluble complex with NH₃. If both give white precipitate insoluble in excess NaOH and insoluble in excess NH₃ but one dissolves in NaOH excess, the logic is:
- Dissolves in excess NaOH, not in NH₃ → Al³⁺
- Does not dissolve in excess NaOH or NH₃ → Mg²⁺
### 5.2 Halide test masked by Cu²⁺ background colour
When adding acidified AgNO₃ to a Cu²⁺-containing sample, the blue colour of the solution makes it hard to see a pale precipitate. The white AgCl precipitate will form, but against a pale blue background it may appear greyish.
**Technique fix.** Use a white tile or place a sheet of white paper under the test tube. Add the AgNO₃ and tilt the tube to look directly down the length of the tube against the white background. The precipitate settles and is more visible at the base than when viewed through the coloured solution from the side.
### 5.3 Anion tests in the presence of NH₄⁺
If the sample also contains NH₄⁺ and you add NaOH before the anion tests, the NaOH will release NH₃ gas from the ammonium. This NH₃ will interfere with the subsequent NH₃ solubility step in cation analysis (you cannot tell if the NH₃ is from your reagent or from the sample). Do the ammonium test early and separately.
---
## 6 | Observation phrasing precision
The difference between zero marks and full marks on an observation line in Paper 4 often comes down to two or three words.
**Colour specificity.** "Blue precipitate" loses marks when the mark scheme says "pale blue gelatinous precipitate". The word "pale" matters because it distinguishes Cu(OH)₂ from, say, a darker cobalt precipitate. The word "gelatinous" distinguishes a hydroxide precipitate from a crystalline one. Use the exact descriptor that the SEAB QA notes associate with each ion.
**Solubility phrasing.** "Dissolves" is ambiguous. Use "dissolves to give a deep blue solution" (Cu²⁺ in excess NH₃) or "insoluble in excess NaOH" (Fe(OH)₃). The inference follows the observation only if the observation specifies what happens, not just that something happened.
**Mixed precipitate phrasing.** When two cations are both present, write: "Initial precipitate is brown with a blue tinge; on addition of excess NH₃, the blue portion dissolves to give a deep blue solution and a reddish-brown residue remains." This phrasing captures both observations and both inferences in one entry, and each half earns its own mark.
**Gas evolution phrasing.** "Colourless gas produced" is not enough. Specify the test: "Colourless gas produced; gas turns moist red litmus blue, indicating NH₃" or "Effervescence, gas turns limewater milky, indicating CO₂." The test performed and the result of the test are both required.
---
## 7 | Full timed walkthrough: Cu²⁺ + Fe³⁺ + SO₄²⁻ + Cl⁻
You receive an aqueous sample labelled A. No other information is given. You have 45 minutes.
### Step 1: Preliminary tests (5 min)
**Flame test.** Dip a clean platinum wire into sample A and hold in a blue Bunsen flame.
*Observation:* Green-blue flame.
*Inference:* Cu²⁺ likely present. (Barium also gives green, but no barium is typically in the ion list for this question type; the specific shade of blue-green points to Cu²⁺.)
**Acid test.** Add a few drops of dilute HCl to a small portion of sample A in a test tube.
*Observation:* No effervescence.
*Inference:* No carbonate or hydrogencarbonate present. $\text{CO}_3^{2-}$ and $\text{HCO}_3^{-}$ are excluded.
**Ammonium test.** Add NaOH(aq) to a separate small portion and warm gently. Hold moist red litmus over the mouth of the tube.
*Observation:* No change to moist red litmus.
*Inference:* No $\text{NH}_4^+$ present.
### Step 2: Cation analysis (15 min)
**NaOH dropwise.** Add NaOH(aq) dropwise to a fresh aliquot of sample A.
*Observation:* Mixed brown-blue precipitate forms.
*Inference:* Presence of at least two cations giving different-coloured hydroxides; likely Cu²⁺ (pale blue) and Fe³⁺ (reddish-brown) given the green-blue flame in the preliminary test.
**NaOH in excess.** Continue adding NaOH until in excess.
*Observation:* Mixed precipitate remains; does not dissolve. No colour change to the precipitate.
*Inference:* Neither cation is amphoteric. Rules out Al³⁺ and Zn²⁺ as the second cation (both dissolve in excess NaOH). Fe³⁺ and Cu²⁺ are consistent.
**NH₃ dropwise, then excess.** Add dilute NH₃(aq) to a fresh aliquot.
*Observation (dropwise):* Mixed brown-blue precipitate forms.
*Observation (excess):* Blue portion of precipitate dissolves to give a deep blue solution. Reddish-brown residue remains and does not dissolve.
*Inference:* Cu²⁺ confirmed — forms $[\text{Cu(NH}_3)_4]^{2+}$, a deep blue complex, on addition of excess NH₃. Fe³⁺ confirmed — $\text{Fe(OH)}_3$ is insoluble in excess NH₃.
$$\text{Cu}^{2+} + 4\text{NH}_3 \rightarrow [\text{Cu(NH}_3)_4]^{2+}$$
$$\text{Fe}^{3+} + 3\text{OH}^{-} \rightarrow \text{Fe(OH)}_3$$
### Step 3: Anion analysis (15 min)
**Acidified BaCl₂.** Add dilute HCl followed by BaCl₂(aq) to a fresh aliquot of the original sample.
*Observation:* White precipitate forms immediately. Precipitate is insoluble in dilute HCl.
*Inference:* $\text{SO}_4^{2-}$ present.
$$\text{Ba}^{2+} + \text{SO}_4^{2-} \rightarrow \text{BaSO}_4 \downarrow$$
**Acidified AgNO₃.** Add dilute HNO₃ followed by AgNO₃(aq) to a separate fresh aliquot of the original sample.
*Observation:* White precipitate forms. Precipitate dissolves in excess dilute NH₃(aq) to give a colourless solution.
*Inference:* Cl⁻ present. (AgCl is soluble in NH₃; AgBr is only partially soluble; AgI is insoluble. The clean dissolution confirms Cl⁻.)
$$\text{Ag}^{+} + \text{Cl}^{-} \rightarrow \text{AgCl} \downarrow$$
$$\text{AgCl} + 2\text{NH}_3 \rightarrow [\text{Ag(NH}_3)_2]^{+} + \text{Cl}^{-}$$
### Step 4: Full inference table
| Test | Observation | Inference |
| --- | --- | --- |
| Flame test | Green-blue flame | Cu²⁺ likely present |
| Dilute HCl | No effervescence | No CO₃²⁻ or HCO₃⁻ |
| NaOH + warming, moist litmus | No change to litmus | No NH₄⁺ |
| NaOH dropwise | Mixed brown-blue precipitate | Two cations present with different hydroxide colours |
| NaOH in excess | Precipitate remains, insoluble | Neither cation amphoteric; Al³⁺, Zn²⁺ excluded |
| NH₃ in excess | Blue portion dissolves (deep blue solution), reddish-brown residue remains | Cu²⁺ confirmed; Fe³⁺ confirmed |
| Acidified BaCl₂ | White precipitate, insoluble in HCl | SO₄²⁻ confirmed |
| Acidified AgNO₃ | White precipitate, dissolves in excess NH₃ | Cl⁻ confirmed |
**Conclusion.** Sample A contains $\text{Cu}^{2+}$, $\text{Fe}^{3+}$, $\text{SO}_4^{2-}$, and $\text{Cl}^{-}$.
---
## 8 | ACE evaluation: what goes wrong and how to argue for marks
### 8.1 Mixed precipitate colour misreading
If you add NaOH quickly rather than dropwise to a two-cation sample, the precipitate forms faster and the colours blend before you can observe each one forming. The observation becomes "brown precipitate" and you lose the Cu²⁺ observation.
**Exam-ready evaluation point:** *Adding NaOH too quickly causes the Cu(OH)₂ precipitate to form inside the Fe(OH)₃ precipitate before both colours can be distinguished separately. This leads to a systematically incorrect observation of "brown precipitate only", missing the pale blue Cu(OH)₂ component and the inference for Cu²⁺. Adding NaOH one drop at a time with 5-second intervals would allow each successive precipitate to form and settle before the next drop changes the observation.*
### 8.2 Cross-contamination between aliquots
Using the same dropper for NaOH and then for AgNO₃ — even after rinsing — can introduce trace OH⁻ into the AgNO₃ test. AgOH is also a white precipitate (though it rapidly darkens). This can give a false positive result or confuse the solubility-in-NH₃ step.
**Exam-ready evaluation point:** *Trace OH⁻ from a shared or inadequately rinsed dropper precipitates AgOH in the AgNO₃ test. AgOH darkens on standing and is only partially soluble in NH₃, which could be misinterpreted as AgBr rather than AgCl. Using a separate disposable Pasteur pipette for each reagent would eliminate this cross-contamination and ensure the white precipitate observed is genuinely AgCl.*
### 8.3 Reagent freshness and AgNO₃ darkening
AgNO₃ solution that has been stored in a clear glass bottle decomposes photochemically to colloidal silver, giving a grey-brown solution background. Any precipitate formed in this solution appears grey rather than white, and a student may record "grey precipitate" rather than "white precipitate".
**Exam-ready evaluation point:** *AgNO₃ stored in clear glassware darkens due to photolytic decomposition to colloidal silver. A grey background solution causes the AgCl precipitate to appear grey rather than white, introducing a systematic error in the observed precipitate colour. Storing AgNO₃ in amber bottles and discarding any solution that has turned grey would eliminate this error.*
### 8.4 Converting qualitative limitation into a quantitative fix
A common ACE pattern is to identify a qualitative limitation — "the end point was judged by colour" — and then convert qualitative limitation into quantitative fix: "replace the colour observation with a turbidimetric measurement using a colorimeter at 540 nm to give a numerical precipitate formation threshold." This pattern shows the examiner that you understand not just what went wrong, but how to design around it.
The same principle applies in QA. Observing "the mixed precipitate colour is ambiguous" is a qualitative limitation. The quantitative fix is: "centrifuge the precipitate and analyse the supernatant spectrophotometrically for residual Cu²⁺ at 620 nm and Fe³⁺ at 450 nm to give independent quantitative confirmation of both cations."
---
## 9 | Next steps
This post has focused on the hardest single QA scenario in Paper 4. For broader coverage:
- [Qualitative Analysis and Organic Workflow for H2 Chemistry Paper 4](https://eclatinstitute.sg/blog/h2-chemistry-experiments/H2-Chemistry-Qualitative-Analysis-Workflow) — foundational workflow, planning scripts, and MMO routine applicable to all QA questions
- [H2 Chemistry Planning and Risk Playbook](https://eclatinstitute.sg/blog/h2-chemistry-experiments/H2-Chemistry-Planning-and-Risk-Playbook) — full planning question framework for Paper 4, including risk assessment and reagent justification
- [H2 Chemistry Experiments hub](https://eclatinstitute.sg/blog/h2-chemistry-experiments) — complete practical guide index for 9476 Paper 4
---
## References
[1] SEAB. (2024). _Chemistry (Syllabus 9476) GCE A-Level 2026._ Singapore Examinations and Assessment Board. (Scheme of Assessment; Paper 4 practical scope; QA notes supplied in exam; ion list for qualitative analysis.)




